求极限limx(sqrt(x^2+100)+x) x趋向于负无穷_数学解答

求极限limx(sqrt(x^2+100)+x) x趋向于负无穷

人气：402 ℃　时间：2020-04-25 14:45:59

解答

limx(sqrt(x^2+100)+x)
=lim100x/(sqrt(x^2+100)-x)
=lim100/(-sqrt(1+100/x^2)-1)
=-50