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关于数学化简题,怎么从[1/(x+1)]*{(x-1)/(x+3)}+1]化简到[1/(x+1)]*[2(X+1)/(X+3)],
人气:236 ℃ 时间:2020-06-13 18:33:15
解答
[1/(x+1)]*{(x-1)/(x+3)}+1]
=[1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)}
=[1/(x+1)]*[2(X+1)/(X+3)]{ [(x-1)+(x+3)] /(x+3)}怎么等于[2(X+1)/(X+3)]1/(x+1)]*{(x-1)/(x+3)+1}=1/(x+1)]*{(x-1)/(x+3)+(x+3)/(x+3)}=1/(x+1)]*{ [(x-1)+(x+3)] /(x+3)}=1/(x+1)]*{ [2x+2] /(x+3)}=1/(x+1)]*[2(X+1)/(X+3)]你那个大括号应该位置错了,在最末尾
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