在命令窗口输入
syms a x c b d
solve('(cos(a + x)*cos(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) - (sin(a + x)*sin(c + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)*cos(a)^2) + (cos(c + x)*sin(a + x)*sin(b + x)*cos(a - b))/(sin(a + c + d + x)*cos(b + x)^2*cos(a)^2) - (cos(a + c + d + x)*cos(c + x)*sin(a + x)*cos(a - b))/(sin(a + c + d + x)^2*cos(b + x)*cos(a)^2)=0','x')
输出答案为
2*atan(z) + 2*pi*kz跟k,代表什么意思啊，怎么会出现那两字母的呢，谢谢整数，z，k都属于整数集整数集？那要怎么显示出来呢你在后面打个括号，里面注：z，k∈Z 就可以了。