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已知二次函数y=-x平方+10x-17,若y的值小于等于8,且大于等于4,则x的取值范围
人气:453 ℃ 时间:2020-05-09 09:46:46
解答
y=-x²+10x-17
=-(x²-10x+25-25)-17
=-(x-5)²+8
4确定正确么- -。确定0<=(x-5)²<=43<=x<=7 这里不应该是 0<=x<=7么?为什么是3x=0,(x-5)²=25, 行吗?0<=(x-5)²<=4-2<=x-5<=23<=x<=7
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