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①∫(1-x)/√9-4x² dx
②∫√x²-9/x dx
③∫dx/√1+e^x
人气:217 ℃ 时间:2020-06-17 08:03:03
解答
①(1-x)/(9-4x^2)^(1\2)=1\2(9\4-x^2)^(1\2)
-4x/4(9-4x^2)^(1\2)
∴∫(1-x)/√9-4x² dx
=(1/2)*arcsin(2x/3)+(1/4)*(9-4x^2)^(1/2)+C
②设x=3sect 0
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