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数学
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(3x^2)^3-[x^3-x(4x^2+1)]+(-x^2)^2 x=1/2
人气:297 ℃ 时间:2020-04-03 14:49:16
解答
(3x^2)^3-7x^3[x^3-x(4x^2+1]+(-x^2)^2=27x^6-7x^3[x^3-4x^3-x]+x^4=27x^6+21x^6+7x^4+x^4=48x^6+8x^4=48/64+1/2=3/4+1/2=5/4你做的是对的!
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