已知|3a-b+1|+|2a+3b-25|=0,求不等式组2ax-7(x-b)>19,ax+(3-b)x>6的解集.
人气：256 ℃ 时间：2020-04-14 07:44:08
解答
3a-b+1=0 b=3a+1
2a+3b-25=0
2a+3（3a+1)-25=0
2a+9a+3-25=0
11a=22
a=2
b=2*3+1=7
4x-7(x-7)>19 4x-7x+49>19 3x6 2x
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