计算：(1-√3i)/(√3+i)^2=A.1/4+(√3/4)iB.-1/4-(√3/4)iC.1/2+(√3/2)iD..-1_数学解答

计算：(1-√3i)/(√3+i)^2=
A.1/4+(√3/4)i
B.-1/4-(√3/4)i
C.1/2+(√3/2)i
D..-1/2-(√3/2)i
是(1-√3*i)/[(√3+i)^2]=?

人气：489 ℃　时间：2020-07-17 22:44:21

解答

(√3+i)^2=2+2√3i
(1-√3i)/(2+2√3i)=(1-√3i)(2-2√3i)/(4+12)=(2-6-4√3i)/16=-(1+√3i)/4
B