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先化简,再求值:3x^3-[x^3+(6x^2-7x)]-2(x^3-3x^2-4x),其中x=-1/3
人气:228 ℃ 时间:2019-10-19 05:44:47
解答
3x^3-[x^3+(6x^2-7x)]-2(x^3-3x^2-4x)
=3x^3-(x^3+6x^2-7x)-2x^3+6x^2+8x
=3x^3-x^3-6x^2+7x-2x^3+6x^2+8x
=15x
=15×(-1/3)
=-5
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