4x^2-xy+3y=0 .(1)式2x^2-y^2-y=0.(2)式由(1)式得到：y=4x^2/(x-3)代入(2)式得到：2x^2-16x^4/(x-3^)^2-4x^2/(x-3)2x^2[1-8x^2/(x-3)^2-2/(x-3)]=0.(3)式 x的第一个解为x1=0,y1=4x1^2/(x1-3)=0当x≠0时,(3)式可化简...