> 数学 >
求z=yarctan(y/x)的全微分,dz/dx,dz/du
- =打错,是dz/dy
人气:221 ℃ 时间:2020-09-30 14:18:58
解答
Z‘x=(-y^2/x^2)/(1+y^2/x^2)=-y^2/(x^2+y^2)
Z‘y=arctan(y/x)+xy/(x^2+y^2)
dz=[-y^2/(x^2+y^2)]dx+[arctan(y/x)+xy/(x^2+y^2)]dy
推荐
猜你喜欢
© 2025 79432.Com All Rights Reserved.
电脑版|手机版