令√[x+2√(x-1)]+√[x-2√(x-1)] =y两边平方得x+2√(x-1)+x-2√(x-1)+2√[x²-4(x-1)] =y²2x+2|x-2|=y²∵x>2∴2x+2x-4=y²∴y=2√(x-1)即√[x+2√(x-1)]+√[x-2√(x-1)] =2√(x-1)...