(cos10°-cos50°)÷(sin10°-sin50°)
人气:166 ℃ 时间:2020-05-20 06:47:22
解答
原式=[cos(30-20)-cos(30+20)]÷[sin(30-20)-sin(30+20)]=(cos30cos20+sin30sin20-cos30cos20+sin30sin20)÷(sin30cos20-cos30sin20-sin30cos20-cos30sin20)=2sin30sin20÷(-2cos30sin20)=-sin30/cos30=-√3/3
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