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解方程组1/(x-y)-1/(x+y)=3/20,2/(x+y)+3/(x-y)=19/20
我给点提示:
1/(x-y)-1/(x+y)=3/20 ①
2/(x+y)+3/(x-y)=19/20 ②
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╮(╯▽╰)╭哎!看来还得问别人了
人气:481 ℃ 时间:2020-05-24 14:49:05
解答
1/(x-y)-1/(x+y)=3/20,
2/(x+y)+3/(x-y)=19/20
设:1/(x-y)=a 1/(x+y)=b
a-b=3/20.1
2b+3a=19/20.2
1式*2+2式:
5a=6/20+19/20=25/20
a=5/20=1/4
b=a-3/20=5/20-3/20=2/20=1/10
1/(x-y)=1/4 x-y=4
1/(x+y)=1/10 x+y=10
相加:2x=14 x=7 相减:2y=6 y=3有点木有看懂认真看一下!很容易啊,代数知识。我学的是方程,朋友!设:1/(x-y)=a 1/(x+y)=b然后把a, b代入原方程,形成两个未知数为a, b的方程。这样可解得a,b值然后,又将a=1/(x-y),1/(x+y)=b 代回来,得x,y值。
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