√(x+1)=t x=t^2-1,dx=2tdtx √(x+1) dx =2(t^4-t^2)dt =2/5t^5-2/3t^3+c 把t带回得 2/5(x+1)^(5/2)-2/3 (x+1)^(3/2)+c
求采纳