∴2011-a=2012-b=2013-c，
∴b=a+1，c=a+2，又abc=24，
则
| a |
| bc |
| b |
| ac |
| c |
| ab |
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
=
| a2+b2+c2 |
| abc |
| bc+ac+ab |
| abc |
=
| a2+b2+c2-bc-ac-ab |
| abc |
=
| a2+(a+1)2+(a+2)2-(a+1)(a+2)-a(a+2)-a(a+1) |
| 24 |
=
| 3 |
| 24 |
| 1 |
| 8 |
故答案为：
| 1 |
| 8 |
| a |
| bc |
| b |
| ac |
| c |
| ab |
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
| a |
| bc |
| b |
| ac |
| c |
| ab |
| 1 |
| a |
| 1 |
| b |
| 1 |
| c |
| a2+b2+c2 |
| abc |
| bc+ac+ab |
| abc |
| a2+b2+c2-bc-ac-ab |
| abc |
| a2+(a+1)2+(a+2)2-(a+1)(a+2)-a(a+2)-a(a+1) |
| 24 |
| 3 |
| 24 |
| 1 |
| 8 |
| 1 |
| 8 |