｜log(1/2)[x/4]｜+1=｜log(1/2)[x^2]｜
｜log(1/2)[x] + 2｜+1 = 2 *｜log(1/2)[x]｜
设 log(1/2)[x] = t
| t + 2 | + 1 = 2 * |t|
这个方程分情况讨论,很容易得到：
t = 3 ,or,t = -1
log(1/2)[x] = 3,-1
x = 1/8 or 2