已知y=√(x－1/2)＋√(1/2－x)＋8,求代数式x²-4y²/x-2y-x/＋y²＋2xy/x²＋xy÷(1/x＋1/y)的值∵(x－1/2)≥0,(1/2－x)≥0∴x－1/2=0x=1/2(x²-4y²)/(x-2y)-x/＋(y²＋2xy)/(x²...