x/(x-3)=2-m/(x-3),
去分母得
x=2(x-3)-m,
x=6+m,
当6+m=3,即m=-3时,原方程有增根.答案是-24啊。我不会过程你说的是(m-3)/(x^2-4)=3x/(2-x)啊，还是x^2-(4/m-3)=2-(3x/x)啊