1.利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]^1/3 2.求二阶导数（y``）：y=_数学解答

1.利用对数求导法求导:y=[(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]^1/3 2.求二阶导数（y``）：y=(x^2-2x+5)^10
1.求极限：lim（x趋向0+）lnx/lnsinx
2.单调区间：y=x-e^x

人气：132 ℃　时间：2019-08-19 09:29:46

解答

1.lny=1/3[ln(x-1)+lnx+ln(x+1)+ln(x+2)-2ln(x-2)-ln(x+3)]y'/y=1/3[1/(x-1)+1/x+1/(x+1)+1/(x+2)-2/(x-2)-1/(x+3)]y'=1/3[1/(x-1)+1/x+1/(x+1)+1/(x+2)-2/(x-2)-1/(x+3)][(x-1)x(x+1)(x+2)/(x-2)^2(x+3)]^1/3 2.y'=...