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解下列三元一次方程组:x/2=y/3=z/5,3x-y+2z=26
人气:329 ℃ 时间:2020-09-23 11:58:04
解答
x/2=y/3 => x=2/3y -------(1)
y/3=z/5 => z=5/3y ------(2)
将(1)(2)代入3x-y+2z=26中
3*2/3y-y+2*5/3y=y+10/3y=13/3y=26 => y=6 => x=4 z=10
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