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解不等式2loga(x-1)≥loga(ax+1)(a>1)
人气:489 ℃ 时间:2020-06-21 06:53:37
解答
2log(x-1)≥log(ax+1)log(x-1)^2≥log(ax+1)x≠1 and ax+1 >0 and (x-1)^2 ≥ ax+1x≠1 and x> 1/a and x^2 - (2+a)x ≥0x≠1 and x> 1/a and "x≤0 or x≥ 1/(2+a)"ie x>1/a
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