500mL 1mol/L的硫酸中,n(H2SO4)=0.5*1 mol = 0.5mol
m(H2SO4)=0.5*98 g=49g=m(浓溶质)
m(浓质)=m(浓液)* a%=0.98m(浓液)
m(浓液)=p(估计密度是1.84g/ml) * V(浓液)=1.84V(浓液)
建立等式m(浓质)=0.98*1.84*V(浓液)=49g
解得V=27.17ml