因式分解法求(x-2)^2-6(x-2)=5=0
人气:311 ℃ 时间:2020-04-21 15:37:29
解答
(x-2)^2-6(x-2)+5=0
设x-2=t
t^2-6t+5=0
(t-5)(t-1)=0
(x-2+5)(x-2-1)=0
(x+3)(x-3)=0
x1=-3 x2=3
推荐
猜你喜欢
- 翻译:Perhaps most puzzling of all,how were we able to make sense of what we heard and distinguish the mistakes and errors
- 邀请外国人合影的英语对话怎么说?
- 已知a=(4,-2,6),b=(-1,4,-2),c=(7,5,λ),且a,b,c三个向量共面,求λ的值.
- 正余弦定理题目
- (1-2)×(2-3)×(3-4)×...×(2004-2005)×(2005-2006)×(2006-2007)×(2007-2008);
- (α1,α2...αr)是线性无关向量组,(β1..βr)=(α1..αr)A,证明r(A)=r(β1.βr)
- 如何测量比量筒口大的大石头的体积.
- 现有0.5mol/L(密度为1.03g/cm)的稀H2SO45L,要配制成5mol/L(密度为1.29g/cm)的H2SO4溶液10L,需加入98%(密度为1.84g/cm)的浓H2SO4和水各多少升