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求值:(1)sin(4π/3)cos(7π/6)tan(21π/4)(2)sin(23π/6)cos(-17π/4)tan(π/8)tan(3π/8)要求详细过程
人气:280 ℃ 时间:2020-05-08 12:25:39
解答
(1)sin(4π/3)cos(7π/6)tan(21π/4)=sin(π+π/3)cos(π+π/6)tan(5π+π/4)=-sinπ/3*(-cosπ/6)tanπ/4=-√3/2*(-√3/2)*1=3/4(2)sin(23π/6)cos(-17π/4)tan(π/8)tan(3π/8)=sin(4π-π/6)cos(-4π-π/4)tan(π...
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