根据所测的热电势为32.865mv,电位差计所处位置的环境温度为36℃,那么热电偶此时测得的电炉的实际温度为:
E(t,0)= E(t,36)+ E(36,0)= 32.865 + 1.448 = 34.313 mv
查K型分度表可知:34.313mv对应的温度值为825.4℃,而所测炉温为790℃,相差35.4℃,所以,显示温度比实际温度低35.4℃,即:
A.热电偶测量的炉内温度是比正常值偏低;
B.实际温度的热电势:
E(825.4,0) = E(825.4,36)+ E(36,0)= 32.865 + 1.448 = 34.313 mv
C.790℃炉内的真实温度,其当时仪表测量的热电势:
查K型分度表可知:790℃温度对应的热电势值为 32.865 mv
E(790,36)= E(790,0) - E(36,0)= 32.685 - 1.448= 31.237 mv