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(4/9)0.5方+(-5.6)lg1方-(2又10/27)-2/3方+0.125-1/3方
人气:301 ℃ 时间:2020-07-02 11:00:31
解答
lg1=0 (4/9)0.5方+(-5.6)lg1方-(2又10/27)-2/3方+0.125-1/3方 =[(2/3)^2]^(0.5)+1-(64/27)^(-2/3)+0.125^(-1/3) =2/3+1-[(4/3)^3])^(-2/3)+(0.5^3)^(-1/3) =2/3+1-9/16+2 =3+2/3-9/16 =3+5/48
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