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化简(ac)/(a-c)-(bc)/(a-b)
人气:363 ℃ 时间:2020-10-01 00:01:47
解答
(ac)/(a-c)-(bc)/(a-b)= (acx(a-b) - bcx(a-c))/((a-c)(a-b))= (ca^2 - abc - abc + b -c^2)/((a-c)(a-b))= (cx(a^2 - 2ab -b^2))/((a-c)(a-b))= (cx(a-b)^2)/((a-c)(a-b))=(c(a-b))/ (a-c)
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