简单解法：
Cu+4HNO3(浓)=Cu(NO3)2+2NO2↑+2H2O
x/2 x
3Cu+8HNO3(稀)=3Cu(NO3)2+2NO↑+4H2O
3y/2 y
n(Cu)=x/2+3y/2=32/64=0.5mol
n(NO+NO2)=x+y=11.2/22.4=0.5mol
x=n(NO2)=0.25mol,y=n(NO)=0.25mol
n(Cu2+)=2n(OH-)=1mol
n(HNO3)=n(Cu2+)/2+n(NO2+NO)=1mol
c(HNO3)=1/0.1=10mol/L