解二元一次方程组(x+3)(y+5)=(x+1)(y+8),(2x-3)(5y+7)=2(5x-6)(y+1)_数学解答

解二元一次方程组(x+3)(y+5)=(x+1)(y+8),(2x-3)(5y+7)=2(5x-6)(y+1)

人气：445 ℃　时间：2019-08-22 00:16:55

解答

┏xy+3y+5x+15＝xy+x+y+8
┗10xy+14x-15y-21=10xy-12y+10x-12
┏2y+4x+7=0①
┗4x-3y-9=0②
①-②得
y=-16/5
x=-3/20