(2/3a^4b^7-1/9a^2b^6)除以(-1/3ab^3)^2=
(x-y)^2-(x+y)(x-y)=
已知x^2+y^2=25,x+y=7且x>y,则x-y的值等于
先化简,再求值:(a+b)(a-b)+b(b+2)=________=________(其中a=根号2,b=-1)
人气:144 ℃ 时间:2019-08-26 05:04:12
解答
原式=(2/3a^4b^7-1/9a^2b^6)÷(1/9a^2b^6)
=2/3a^4b^7÷(1/9a^2b^6)-1/9a^2b^6÷(1/9a^2b^6)
=6a^2b-1
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