解；因为函数的周期为π
所以f（8π/3）=f(2π/3+2π)=f(2π/3)=f(-π/3+π）=f(-π/3)
又因为f(x)为偶函数,所以f(-π/3)=f(π/3)
所以f(8π/3)=f(π/3)
=√3×√3-1
=2