若x^2+3x-(1)/(3)=0,则（x-3)/（3x^2-6x）/[x+2-(5)/(x-2)]的值是多少_数学解答

若x^2+3x-(1)/(3)=0,则（x-3)/（3x^2-6x）/[x+2-(5)/(x-2)]的值是多少

人气：252 ℃　时间：2020-04-30 04:18:57

解答

（x-3)/（3x^2-6x）/[x+2-(5)/(x-2)] =（x-3)/ (3x) /（x-2）/[x+2-(5)/(x-2)]=（x-3)/ (3x) /[(x+2)(x-2)- 5]=（x-3)/ (3x) /[x^2 - 9]= 1 / [3x(x+3)]= 1/3 /[x^2+3x] (x^2+3x-(1)/(3)=0,x^2+3x =1/3) =1/3 / (1/3...