先化简再求值3xyz+2(x^2y+y^2z-xyz)-xyz+2z^2x x=1 y= -1 z=2
人气：101 ℃ 时间：2020-03-31 18:40:53
解答
3xyz+2(x^2y+y^2z-xyz)-xyz+2z^2x
原式= 3xyz+2（x²y+y²z+z²x）-3xyz
=2（x²y+y²z+z²x）
=2×(-1+2+4)
=2×5
=10
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