解方程：x²-2(1+√2)x+2√2=0,
[x²-2(1+√2)x+(1+√2)²]+[2√2-(1+√2)²]=0,
[x-(1+√2)]²-3=0,
[(x-1-√2)+√3]*[(x-1-√2)-√3]=0,
(x-1-√2+√3)(x-1-√2-√3)=0,
由x-1-√2+√3=0得x1=1+√2-√3：
由x-1-√2-√3=0得x2=1+√2+√3..