已知x+y-z=-1,x^2+y^2-z^2=-11,求代数式(2x-3y^2+2y)-(3x^2-3z^2+2z)的值.
已知x+y-z=-1,x^2+y^2-z^2=-11,求代数式(2x-3y^2+2y)-(3x^2-3z^2+2z)的值.
人气:485 ℃ 时间:2019-10-29 12:05:26
解答
这个其实很简单,把括号去掉,整理整理
原式=2x+2y-2z-3x^2-3y^2+3z^2
=2(x+y-z)-3(x^2+y^2-z^2)
=-2+33=31
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