(2005x)(2005x)-2004*2006x-1=0用分解因式法怎么解
人气：450 ℃ 时间：2020-02-22 18:00:57
解答
2005²=2004*2006+1
所以2004*2006x²+x²-2004*2006x-1=0
2004*2006x(x-1)+(x+1)(x-1)=0
(x-1)(2004*2006x+x+1)=0
x=1,x=-1/(2004*2006+1)
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