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用因式分解法解方程:(1+根号2)x²-(1-根号2)x=0
LL还没上初三,开学要学啊.
人气:246 ℃ 时间:2019-10-19 17:58:44
解答
(1+√2)x²-(1-√2)x=0
x{(1+√2)x-(1-√2)}=0
x1=0
x2=(1-√2)/(1+√2)=(1-√2)^2/(1+√2)(1-√2)=(2-2√2+1)/(1-2)=2√2-3x2=(1-√2)/(1+√2)=(1-√2)^2/(1+√2)(1-√2)=(2-2√2+1)/(1-2)=2√2-3 ????? “/”中间的这个是什么符号啊?分数线从{(1+√2)x-(1-√2)}到(1-√2)/(1+√2)怎么来的。求分析。(1+√2)x-(1-√2)=0(1+√2)x=(1-√2)x=(1-√2)/(1+√2)
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