左边只需要乘以2*sin((x-x0)/2),利用积化和差公式,
左边*2 sin((x-x0)/2)
=sin ((x-x0)/2)-sin((x-x0)/2)+sin(3(x-x0)/2)-sin(3(x-x0)/2)+sin(3(x-x0)/2)
+...-sin((2n-1)*(x-x0)/2)+sin((2n+1)*(x-x0)/2)
=sin[(n+1/2)*(x-x0)]
证得结果