=2x/(x-1)+1/(x+3)-(3x+5)/(x+3)(x-1)
=[2x(x+3)+(x-1)-(3x+5)]/(x+3)(x-1)
=(2x²+6x+x-1-3x-5)/(x+3)(x-1)
=(2x²+4x-6)/(x²+2x-3)
=2