己知a方减a的负2次幂等于2(a-a负1次幂)则a=?
计算过程
人气:260 ℃ 时间:2019-10-24 08:06:03
解答
a^2-1/a^2=2(a-1/a),
(a-1/a)(a+1/a)-2(a-1/a)=0,
(a-1/a)(a+1/a-2)=0,
[(a^2-1)]/a*[(a-1)^2/a]=0,
(a+1)(a-1)^3/a^2=0,
a=±1.
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