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求解lim(x->1) (2x/(x+1))^(2x/(x+1))
答案是(5/2)^(5/2)吗?说是用特殊极限求解,我也导不成x趋于无穷大时lim(1+1/x)^x=e的形式啊?还望赐教
人气:335 ℃ 时间:2020-10-02 05:37:42
解答
lim(x->1) (2x/(x+1))^(2x/(x+1))
=lim(x->1) e^ln(2x/(x+1))^(2x/(x+1))
=lim(x->1) e^(2x/(x+1))ln(2x/(x+1))
=1 [lim(x->1) (2x/(x+1))ln(2x/(x+1))=0,e为常数]
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