[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²]=[2x²-(x²-y²)][(x+y)(x-y)+2y²]=(2x²-x²+y²)(x²-y²+2y²)=(x²+y²)²=(1²+2²)²=5&...请问一下就是原式那个答案在哪呢？25是正确答案，25的上一个式子的答案在哪里？[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²]=[2x²-(x²-y²)][(x+y)(x-y)+2y²]=(2x²-x²+y²)(x²-y²+2y²)=(x²+y²)²=(1²+2²)²=(1+4)²=5²=25