(x^2+1)-7(x^2+1)+10
=(x²+1-2)(x²+1-5)
=(x²-1)(x²-4)
=(x-1)(x+1)(x-2)(x+2)
(x^2+5x)(x^2+5x-2)-24
=(x²+5x)²-2(x²+5x)-24
=(x²+5x-6)(x²+5x+4)
=(x+6)(x-1)(x+1)(x+4)
（a+1）^2+2(a+1)-8
=(a+1+4)(a+1-2)
=(a+5)(a-1)SORRY第一题打错了，是（x^2+1）^2-7(x^2+-7)+10,帮忙解答一下，多谢啦(x^2+1)²-7(x^2+1)+10=(x²+1-2)(x²+1-5)=(x²-1)(x²-4)=(x-1)(x+1)(x-2)(x+2)