一道二次函数题目甲乙两人进行羽毛球比赛,甲发球,出手点为P,羽毛球飞出的水平距离s与球距地面高度h之间的函数解析式为h=十二分之一_数学解答

答：h=(1/12)s^2+(2/3)s+3/2是开口向上的抛物线,与羽毛球轨迹是开口向下的抛物线矛盾,请检查题目h=-(1/12)s^2+(2/3)s+3/2=-(1/12)(s^2-8s+16)+17/6=-(1/12)(s-4)^2+17/6s=m>5时：h=-(1/12)m^2+(2/3)m+3/2>4/9-(1/12)...抱歉，是-十二分之一s平方答：h=-(1/12)s^2+(2/3)s+3/2=-(1/12)(s^2-8s+16)+17/6=-(1/12)(s-4)^2+17/6s=m>5时：h=-(1/12)m^2+(2/3)m+3/2>4/9-(1/12)(m-4)^2+17/6>4/9(1/12)(m-4)^2<43/18(m-4)^2<86/3m<4+√(86/3)所以：5