y(x)=sin(x²+1)
y'(x)=cos(x²+1)*(2x)=2xcos(x²+1)这是怎么求出来的？复杂导数我就是没明白。。。。这个是复合函数u=g(y) y=f(x)则 u'=g'(y)*f'(x)在这里y'(x)=[sin(x²+1)]' × (x²+1)'=cos(x²+1) × (2x)=2xcos(x²+1)