杨辉三角 3^5-5*3^4+10*3^3-10*3^2+5*3-1_数学解答

杨辉三角 3^5-5*3^4+10*3^3-10*3^2+5*3-1

人气：133 ℃　时间：2020-05-18 22:25:30

解答

3^5-5*3^4+10*3^3-10*3^2+5*3-1
=3*3^4-5*3^4+10*3^3-10*3^2+5*3-1
=-2*3^4+10*3^3-10*3^2+5*3-1
=-6*3^3+10*3^3-10*3^2+5*3-1
=4*3^3-10*3^2+5*3-1
=12*3^2-10*3^2+5*3-1
=2*3^2+5*3-1
=6*3+5*3-1
=11*3-1
=33-1
=32