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杨辉三角 3^5-5*3^4+10*3^3-10*3^2+5*3-1
人气:284 ℃ 时间:2020-05-18 22:25:30
解答
3^5-5*3^4+10*3^3-10*3^2+5*3-1
=3*3^4-5*3^4+10*3^3-10*3^2+5*3-1
=-2*3^4+10*3^3-10*3^2+5*3-1
=-6*3^3+10*3^3-10*3^2+5*3-1
=4*3^3-10*3^2+5*3-1
=12*3^2-10*3^2+5*3-1
=2*3^2+5*3-1
=6*3+5*3-1
=11*3-1
=33-1
=32
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