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∫㏑(1+t²)dt
人气:357 ℃ 时间:2020-10-01 20:46:37
解答
∫㏑(1+t^2)dt
=tln(1+t^2) - 2∫t^2/(1+t^2)dt
=tln(1+t^2) - 2∫(t^2+1)/(1+t^2)dt +2∫dt/(1+t^2)
=tln(1+t^2) - 2t +2arctan(t) + C
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