解析：∵log(1/2)│1+1/x│＞log(1/2)1/2,
又0＜1/2＜1,y=log(1/2)x,x＞0为单调递减,
∴│1+1/x│＜1/2,
即-1/2＜1+1/x＜1/2,
得-2＜x＜-2/3