y=sinx+2/1-cosx的值域
y=(sinx+2)/(1-cosx)的值域
人气:293 ℃ 时间:2020-05-20 23:43:39
解答
化解Y:
分子=sinx+2=2sin(x/2)cos(x/2)+2sin(x/2)^2+2cos(x/2)^2
分母=2sin(x/2)^2
所以Y=(cos(x/2)/sin(x/2))^2+cos(x/2)/sin(x/2)+1
设u=cos(x/2)/sin(x/2)=cot(x/2)
则Y=u^2+u+1
下面相当于求抛物线的值域了哦
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